Lemma 42.2.3. Let $R$ be a ring. Suppose that we have a short exact sequence of $2$-periodic complexes
If two out of three have cohomology modules of finite length so does the third and we have
Lemma 42.2.3. Let $R$ be a ring. Suppose that we have a short exact sequence of $2$-periodic complexes
If two out of three have cohomology modules of finite length so does the third and we have
Proof. We abbreviate $A = (M_1, N_1, \varphi _1, \psi _1)$, $B = (M_2, N_2, \varphi _2, \psi _2)$ and $C = (M_3, N_3, \varphi _3, \psi _3)$. We have a long exact cohomology sequence
This gives a finite exact sequence
with $0 \to K \to H^1(C) \to I \to 0$ a filtration. By additivity of the length function (Algebra, Lemma 10.52.3) we see the result. $\square$
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