Lemma 94.6.1. Let $f : X \to Y$ be a morphism of $(\mathit{Sch}/S)_{fppf}$. Then the $1$-morphism induced by $f$
\[ (\mathit{Sch}/X)_{fppf} \longrightarrow (\mathit{Sch}/Y)_{fppf} \]
is a representable $1$-morphism.
Lemma 94.6.1. Let $f : X \to Y$ be a morphism of $(\mathit{Sch}/S)_{fppf}$. Then the $1$-morphism induced by $f$
is a representable $1$-morphism.
Proof. This is formal and relies only on the fact that the category $(\mathit{Sch}/S)_{fppf}$ has fibre products. $\square$
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Comments (2)
Comment #7706 by Mingchen on
Comment #7966 by Stacks Project on