Lemma 65.11.3. Let $S$ be a scheme contained in $\mathit{Sch}_{fppf}$. Let $F$ be an algebraic space over $S$. Let $G \to F$ be a representable transformation of functors. Then $G$ is an algebraic space.
A functor that admits a representable morphism to an algebraic space is an algebraic space.
Proof.
By Lemma 65.3.5 we see that $G$ is a sheaf. The diagram
is cartesian. Hence we see that $G \times _ F G \to G \times G$ is representable by Lemma 65.3.3. By Lemma 65.3.6 we see that $G \to G \times _ F G$ is representable. Hence $\Delta _ G : G \to G \times G$ is representable as a composition of representable transformations, see Lemma 65.3.2. Finally, let $U$ be an object of $(\mathit{Sch}/S)_{fppf}$ and let $U \to F$ be surjective and étale. By assumption $U \times _ F G$ is representable by a scheme $U'$. By Lemma 65.5.5 the morphism $U' \to G$ is surjective and étale. This verifies the final condition of Definition 65.6.1 and we win.
$\square$
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Comment #893 by Kestutis Cesnavicius on