Lemma 42.39.1. Let $(S, \delta )$ be as in Situation 42.7.1. Let $X$ be locally of finite type over $S$. Let $\mathcal{E}$ be a finite locally free sheaf of rank $r$ on $X$. Let $\mathcal{L}$ be an invertible sheaf on $X$. Then we have
in $A^*(X)$.
Lemma 42.39.1. Let $(S, \delta )$ be as in Situation 42.7.1. Let $X$ be locally of finite type over $S$. Let $\mathcal{E}$ be a finite locally free sheaf of rank $r$ on $X$. Let $\mathcal{L}$ be an invertible sheaf on $X$. Then we have
in $A^*(X)$.
Proof. This should hold for any triple $(X, \mathcal{E}, \mathcal{L})$. In particular it should hold when $X$ is integral and by Lemma 42.35.3 it is enough to prove it holds when capping with $[X]$ for such $X$. Thus assume that $X$ is integral. Let $(\pi : P \to X, \mathcal{O}_ P(1))$, resp. $(\pi ' : P' \to X, \mathcal{O}_{P'}(1))$ be the projective space bundle associated to $\mathcal{E}$, resp. $\mathcal{E} \otimes \mathcal{L}$. Consider the canonical morphism
see Constructions, Lemma 27.20.1. It has the property that $g^*\mathcal{O}_{P'}(1) = \mathcal{O}_ P(1) \otimes \pi ^* {\mathcal L}$. This means that we have
in $\mathop{\mathrm{CH}}\nolimits _*(P)$, where $\xi $ represents $c_1(\mathcal{O}_ P(1))$ and $x$ represents $c_1(\pi ^*\mathcal{L})$. By simple algebra this is equivalent to
Comparing with Equation (42.37.1.1) it follows from this that
Reworking this (getting rid of minus signs, and renumbering) we get the desired relation. $\square$
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