24.32 Miscellany
Let $(f, f^\sharp ) : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}'), \mathcal{O}')$ be a morphism of ringed topoi. Let $\mathcal{A}$ be a sheaf of differential graded $\mathcal{O}$-algebras. Using the composition1
and the relative cup product (see Cohomology on Sites, Remark 21.19.7 and Section 21.33) we obtain a multiplication2
in $D(\mathcal{O}')$. This multiplication is associative in the sense that the diagram
commutes in $D(\mathcal{O}')$; this follows from Cohomology on Sites, Lemma 21.33.2. In exactly the same way, given a right differential graded $\mathcal{A}$-module $\mathcal{M}$ we obtain a multiplication
in $D(\mathcal{O}')$. This multiplication is compatible with $\mu $ above in the sense that the diagram
commutes in $D(\mathcal{O}')$; again this follows from Cohomology on Sites, Lemma 21.33.2.
A particular example of the above is when one takes $f$ to be the morphism to the punctual topos $\mathop{\mathit{Sh}}\nolimits (pt)$. In that case $\mu $ is just the cup product map
and similarly $\mu _\mathcal {M}$ is the cup product map
In general, via the identifications
of Cohomology on Sites, Remark 21.14.4 the map $\mu _\mathcal {M}$ induces the cup product on cohomology. To see this use Cohomology on Sites, Lemma 21.33.4 where the second morphism of topoi is the morphism from $\mathop{\mathit{Sh}}\nolimits (\mathcal{C}')$ to the punctual topos as above.
If $\mathcal{M}_1 \to \mathcal{M}_2$ is a homomorphism of right differential graded $\mathcal{A}$-modules, then the diagram
commutes in $D(\mathcal{O}')$; this follows from the fact that the relative cup product is functorial. Suppose we have a short exact sequence
of right differential graded $\mathcal{A}$-modules. Then we claim that the diagram
commutes in $D(\mathcal{O}')$ where $\delta : \mathcal{M}_3 \to \mathcal{M}_1[1]$ is the morphism of $D(\mathcal{O})$ coming from the given short exact sequence (see Derived Categories, Section 13.12). This is clear if our sequence is split as a sequence of graded right $\mathcal{A}$-modules, because in this case $\delta $ can be represented by a map of right $\mathcal{A}$-modules and the discussion above applies. In general we argue using the cone on $a$ and the diagram
where the right square is commutative in $D(\mathcal{O})$ by the definition of $\delta $ in Derived Categories, Lemma 13.12.1. Now the cone $C(a)$ has the structure of a right differential graded $\mathcal{A}$-module such that $i$, $p$, $q$ are homomorphisms of right differential graded $\mathcal{A}$-modules, see Definition 24.22.2. Hence by the above we know that the corresponding diagrams commute for the morphisms $q$ and $-p$. Since $q$ is an isomorphism in $D(\mathcal{O})$ we conclude the same is true for $\delta $ as desired.
In the situation above given a right differential graded $\mathcal{A}$-module $\mathcal{M}$ let
In other words, $\xi $ is a degree $n$ cohomology class in the cohomology of $\mathcal{M}$ viewed as a complex of $\mathcal{O}$-modules. By Lemma 24.29.9 we can construct maps
of right differential graded $\mathcal{A}$-modules where $s$ is a quasi-isomorphism and such that $\xi $ is the image of $1 \in H^0(\mathcal{C}, \mathcal{A})$ via the morphism $s[n]^{-1} \circ x$ in the derived category $D(\mathcal{A}, \text{d})$ and a fortiori in the derived category $D(\mathcal{O})$. It follows that the corresponding map
in $D(\mathcal{O})$ is uniquely characterized by the following two properties
$\xi '$ can be lifted to a morphism in $D(\mathcal{A}, \text{d})$, and
$\xi = \xi '(1)$ in $H^0(\mathcal{C}, \mathcal{M}[n]) = H^ n(\mathcal{C}, \mathcal{M})$.
Using the compatibilities of $x$ and $s$ with the relative cup product discussed above it follows that for every3 morphism of ringed topoi $(f, f^\sharp ) : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}'), \mathcal{O}')$ the derived pushforward
of $\xi '$ is compatible with the maps $\mu $ and $\mu _{\mathcal{M}[n]}$ constructed above in the sense that the diagram
commutes in $D(\mathcal{O}')$. Using this compatibility for the map to the punctual topos, we see in particular that
commutes. Combined with $\xi '(1) = \xi $ this implies that the induced map on cohomology
is given by left cup product by $\xi $ as indicated.
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