The Stacks project

Lemma 52.5.3. Let $(A, \mathfrak m)$ be a Noetherian local ring. Let $(M_ n)$ be an inverse system of finite $A$-modules. Let $M \to \mathop{\mathrm{lim}}\nolimits M_ n$ be a map where $M$ is a finite $A$-module such that for some $i$ the map $H^ i_\mathfrak m(M) \to \mathop{\mathrm{lim}}\nolimits H^ i_\mathfrak m(M_ n)$ is an isomorphism. Then the inverse system $H^ i_\mathfrak m(M_ n)$ is essentially constant with value $H^ i_\mathfrak m(M)$.

Proof. By Lemma 52.5.2 the inverse system $H^ i_\mathfrak m(M_ n)$ satisfies the Mittag-Leffler condition. Let $E_ n \subset H^ i_\mathfrak m(M_ n)$ be the image of $H^ i_\mathfrak m(M_{n'})$ for $n' \gg n$. Then $(E_ n)$ is an inverse system with surjective transition maps and $H^ i_\mathfrak m(M) = \mathop{\mathrm{lim}}\nolimits E_ n$. Since $H^ i_\mathfrak m(M)$ has the descending chain condition by Lemma 52.5.1 we find there can only be a finite number of nontrivial kernels of the surjections $H^ i_\mathfrak m(M) \to E_ n$. Thus $E_ n \to E_{n - 1}$ is an isomorphism for all $n \gg 0$ as desired. $\square$


Comments (0)


Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 0EHB. Beware of the difference between the letter 'O' and the digit '0'.