Lemma 109.17.1. The inclusion
is that of an open dense subset.
Lemma 109.17.1. The inclusion
is that of an open dense subset.
Proof. By the very construction of the topology on $|\mathcal{C}\! \mathit{urves}^{lci+}|$ in Properties of Stacks, Section 100.4 we find that $|\mathcal{C}\! \mathit{urves}^{smooth}|$ is an open subset. Let $\xi \in |\mathcal{C}\! \mathit{urves}^{lci+}|$ be a point. Then there exists a field $k$ and a scheme $X$ over $k$ with $X$ proper over $k$, with $\dim (X) \leq 1$, with $X$ a local complete intersection over $k$, and with $X$ is smooth over $k$ except at finitely many points, such that $\xi $ is the equivalence class of the classifying morphism $\mathop{\mathrm{Spec}}(k) \to \mathcal{C}\! \mathit{urves}^{lci+}$ determined by $X$. See Lemma 109.15.2. By Deformation Problems, Lemma 93.17.6 there exists a flat projective morphism $Y \to \mathop{\mathrm{Spec}}(k[[t]])$ whose generic fibre is smooth and whose special fibre is isomorphic to $X$. Consider the classifying morphism
determined by $Y$. The image of the closed point is $\xi $ and the image of the generic point is in $|\mathcal{C}\! \mathit{urves}^{smooth}|$. Since the generic point specializes to the closed point in $|\mathop{\mathrm{Spec}}(k[[t]])|$ we conclude that $\xi $ is in the closure of $|\mathcal{C}\! \mathit{urves}^{smooth}|$ as desired. $\square$
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