Lemma 53.21.3. In Situation 53.6.2 assume $X$ is integral and has genus $g$. Let $\mathcal{L}$ be an invertible $\mathcal{O}_ X$-module. If $\deg (\mathcal{L}) \geq 2g$, then $\mathcal{L}$ is globally generated.
[Lemma 3, Jongmin]
Proof.
Let $Z \subset X$ be the closed subscheme cut out by the global sections of $\mathcal{L}$. By Lemma 53.21.2 we see that $Z \not= X$. Let $\mathcal{I} \subset \mathcal{O}_ X$ be the ideal sheaf cutting out $Z$. Consider the short exact sequence
If $Z \not= \emptyset $, then $H^1(X, \mathcal{I}\mathcal{L})$ is nonzero as follows from the long exact sequence of cohomology. By Lemma 53.4.2 this gives a nonzero and hence injective map
In particular, we find an injective map $H^0(X, \mathcal{L}) = H^0(X, \mathcal{I}\mathcal{L}) \to H^0(X, \omega _ X)$. This is impossible as
and $\dim H^0(X, \omega _ X) = g$ by (53.8.1.1).
$\square$
Post a comment
Your email address will not be published. Required fields are marked.
In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$
). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).
All contributions are licensed under the GNU Free Documentation License.
Comments (0)