Lemma 58.22.2. In Situation 58.19.1 assume
$A$ has a dualizing complex and is $f$-adically complete,
every irreducible component of $X$ not contained in $X_0$ has dimension $\geq 3$.
Then the restriction functor
is fully faithful.
Lemma 58.22.2. In Situation 58.19.1 assume
$A$ has a dualizing complex and is $f$-adically complete,
every irreducible component of $X$ not contained in $X_0$ has dimension $\geq 3$.
Then the restriction functor
is fully faithful.
Proof. To prove this we may replace $A$ by its reduction by the topological invariance of the fundamental group, see Lemma 58.8.3. Then the result follows from Lemma 58.17.3 and Algebraic and Formal Geometry, Lemma 52.15.7. $\square$
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