Lemma 31.18.3. Let $f : X \to S$ be a morphism of schemes. If $D_1, D_2 \subset X$ are relative effective Cartier divisor on $X/S$ then so is $D_1 + D_2$ (Definition 31.13.6).
Proof. This translates into the following algebra fact: Let $A \to B$ be a ring map and $h_1, h_2 \in B$. Assume the $h_ i$ are nonzerodivisors and that $B/h_ iB$ is flat over $A$. Then $h_1h_2$ is a nonzerodivisor and $B/h_1h_2B$ is flat over $A$. The reason is that we have a short exact sequence
where the first arrow is given by multiplication by $h_2$. Since the outer two are flat modules over $A$, so is the middle one, see Algebra, Lemma 10.39.13. $\square$
Post a comment
Your email address will not be published. Required fields are marked.
In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$
). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).
All contributions are licensed under the GNU Free Documentation License.
Comments (0)