The Stacks project

5.29 Colimits of spaces

The category of topological spaces has coproducts. Namely, if $I$ is a set and for $i \in I$ we are given a topological space $X_ i$ then we endow the set $\coprod _{i \in I} X_ i$ with the coproduct topology. As a basis for this topology we use sets of the form $U_ i$ where $U_ i \subset X_ i$ is open.

The category of topological spaces has coequalizers. Namely, if $a, b : X \to Y$ are morphisms of topological spaces, then the coequalizer of $a$ and $b$ is the coequalizer $Y/\sim $ in the category of sets endowed with the quotient topology (Section 5.6).

Lemma 5.29.1. The category of topological spaces has colimits and the forgetful functor to sets commutes with them.

Proof. This follows from the discussion above and Categories, Lemma 4.14.12. Another proof of existence of colimits is sketched in Categories, Remark 4.25.2. It follows from the above that the forgetful functor commutes with colimits. Another way to see this is to use Categories, Lemma 4.24.5 and use that the forgetful functor has a right adjoint, namely the functor which assigns to a set the corresponding chaotic (or indiscrete) topological space. $\square$


Comments (2)

Comment #4910 by PRH on

There seems to be a typo in the second paragraph, which should say "the coequalizer of and ."


Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 0B1W. Beware of the difference between the letter 'O' and the digit '0'.