The Stacks project

Remark 52.6.14 (Localization and derived completion). Let $(\mathcal{C}, \mathcal{O})$ be a ringed site. Let $\mathcal{I} \subset \mathcal{O}$ be a finite type sheaf of ideals. Let $K \mapsto K^\wedge $ be the derived completion functor of Proposition 52.6.12. It follows from the construction in the proof of the proposition that $K^\wedge |_ U$ is the derived completion of $K|_ U$ for any $U \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{C})$. But we can also prove this as follows. From the definition of derived complete objects it follows that $K^\wedge |_ U$ is derived complete. Thus we obtain a canonical map $a : (K|_ U)^\wedge \to K^\wedge |_ U$. On the other hand, if $E$ is a derived complete object of $D(\mathcal{O}_ U)$, then $Rj_*E$ is a derived complete object of $D(\mathcal{O})$ by Lemma 52.6.7. Here $j$ is the localization morphism (Modules on Sites, Section 18.19). Hence we also obtain a canonical map $b : K^\wedge \to Rj_*((K|_ U)^\wedge )$. We omit the (formal) verification that the adjoint of $b$ is the inverse of $a$.


Comments (0)

There are also:

  • 2 comment(s) on Section 52.6: Derived completion on a ringed site

Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 0A0F. Beware of the difference between the letter 'O' and the digit '0'.