The Stacks project

Example 98.22.3. Let $S = \mathop{\mathrm{Spec}}(\Lambda )$ for some Noetherian ring $\Lambda $. Let $W \to S$ be a morphism of schemes. Let $\mathcal{F}$ be a quasi-coherent $\mathcal{O}_ W$-module flat over $S$. Consider the functor

\[ F : (\mathit{Sch}/S)_{fppf}^{opp} \longrightarrow \textit{Sets}, \quad T/S \longrightarrow H^0(W_ T, \mathcal{F}_ T) \]

where $W_ T = T \times _ S W$ is the base change and $\mathcal{F}_ T$ is the pullback of $\mathcal{F}$ to $W_ T$. If $T = \mathop{\mathrm{Spec}}(A)$ we will write $W_ T = W_ A$, etc. Let $\mathcal{X} \to (\mathit{Sch}/S)_{fppf}$ be the category fibred in groupoids associated to $F$. Then $\mathcal{X}$ has an obstruction theory. Namely,

  1. given $A$ over $\Lambda $ and $x \in H^0(W_ A, \mathcal{F}_ A)$ we set $\mathcal{O}_ x(M) = H^1(W_ A, \mathcal{F}_ A \otimes _ A M)$,

  2. given a deformation situation $(x, A' \to A)$ we let $o_ x(A') \in \mathcal{O}_ x(A)$ be the image of $x$ under the boundary map

    \[ H^0(W_ A, \mathcal{F}_ A) \longrightarrow H^1(W_ A, \mathcal{F}_ A \otimes _ A I) \]

    coming from the short exact sequence of modules

    \[ 0 \to \mathcal{F}_ A \otimes _ A I \to \mathcal{F}_{A'} \to \mathcal{F}_ A \to 0. \]

We have omitted some details, in particular the construction of the short exact sequence above (it uses that $W_ A$ and $W_{A'}$ have the same underlying topological space) and the explanation for why flatness of $\mathcal{F}$ over $S$ implies that the sequence above is short exact.


Comments (0)


Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 07YH. Beware of the difference between the letter 'O' and the digit '0'.