The Stacks project

Proof. We will prove this by showing the functor $R\epsilon _* : D(\mathcal{O}_{\acute{e}tale}) \to D(\mathcal{O}_ X)$ induces a quasi-inverse. We will use freely that $\epsilon _*$ is given by restriction to $X_{Zar} \subset X_{\acute{e}tale}$ and the description of $\epsilon ^* = \text{id}_{small, {\acute{e}tale}, Zar}^*$ in Descent, Lemma 35.8.5.

For a quasi-coherent $\mathcal{O}_ X$-module $\mathcal{F}$ the adjunction map $\mathcal{F} \to \epsilon _*\epsilon ^*\mathcal{F}$ is an isomorphism by the fact that $\mathcal{F}^ a$ (Descent, Definition 35.8.2) is a sheaf as proved in Descent, Lemma 35.8.1. Conversely, every quasi-coherent $\mathcal{O}_{\acute{e}tale}$-module $\mathcal{H}$ is of the form $\epsilon ^*\mathcal{F}$ for some quasi-coherent $\mathcal{O}_ X$-module $\mathcal{F}$, see Descent, Proposition 35.8.9. Then $\mathcal{F} = \epsilon _*\mathcal{H}$ by what we just said and we conclude that the adjunction map $\epsilon ^*\epsilon _*\mathcal{H} \to \mathcal{H}$ is an isomorphism for all quasi-coherent $\mathcal{O}_{\acute{e}tale}$-modules $\mathcal{H}$.

Let $E$ be an object of $D_\mathit{QCoh}(\mathcal{O}_{\acute{e}tale})$ and denote $\mathcal{H}^ q = H^ q(E)$ its $q$th cohomology sheaf. Let $\mathcal{B}$ be the set of affine objects of $X_{\acute{e}tale}$. Then $H^ p(U, \mathcal{H}^ q) = 0$ for all $p > 0$, all $q \in \mathbf{Z}$, and all $U \in \mathcal{B}$, see Descent, Proposition 35.9.3 and Cohomology of Schemes, Lemma 30.2.2. By Cohomology on Sites, Lemma 21.23.11 this means that

for all $U \in \mathcal{B}$. In particular, we find that this holds for affine opens $U \subset X$. It follows that the $q$th cohomology of $R\epsilon _*E$ over $U$ is the value of the sheaf $\epsilon _*\mathcal{H}^ q$ over $U$. Applying sheafification we obtain

which in particular shows that $R\epsilon _*$ induces a functor $D_\mathit{QCoh}(\mathcal{O}_{\acute{e}tale}) \to D_\mathit{QCoh}(\mathcal{O}_ X)$. Since $\epsilon ^*$ is exact we then obtain $H^ q(\epsilon ^*R\epsilon _*E) = \epsilon ^*\epsilon _*\mathcal{H}^ q = \mathcal{H}^ q$ (by discussion above). Thus the adjunction map $\epsilon ^*R\epsilon _*E \to E$ is an isomorphism.

Conversely, for $F \in D_\mathit{QCoh}(\mathcal{O}_ X)$ the adjunction map $F \to R\epsilon _*\epsilon ^*F$ is an isomorphism for the same reason, i.e., because the cohomology sheaves of $R\epsilon _*\epsilon ^*F$ are isomorphic to $\epsilon _*H^ m(\epsilon ^*F) = \epsilon _*\epsilon ^*H^ m(F) = H^ m(F)$. $\square$