Lemma 76.48.6. Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The following are equivalent
$f$ is flat and a local complete intersection morphism, and
$f$ is syntomic.
Syntomic equals flat plus lci (for algebraic spaces).
Lemma 76.48.6. Let $S$ be a scheme. Let $f : X \to Y$ be a morphism of algebraic spaces over $S$. The following are equivalent
$f$ is flat and a local complete intersection morphism, and
$f$ is syntomic.
Proof. Omitted. Hint: Use the schemes version of this lemma, see More on Morphisms, Lemma 37.62.8. $\square$
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Comment #858 by Bhargav Bhatt on