110.16 A Noetherian ring of infinite dimension
A Noetherian local ring has finite dimension as we saw in Algebra, Proposition 10.60.9. But there exist Noetherian rings of infinite dimension. See [Appendix, Example 1, Nagata].
Namely, let $k$ be a field, and consider the ring
Let $\mathfrak p_ i = (x_{2^{i - 1}}, x_{2^{i - 1} + 1}, \ldots , x_{2^ i - 1})$ for $i = 1, 2, \ldots $ which are prime ideals of $R$. Let $S$ be the multiplicative subset
Consider the ring $A = S^{-1}R$. We claim that
The maximal ideals of the ring $A$ are the ideals $\mathfrak m_ i = \mathfrak p_ iA$.
We have $A_{\mathfrak m_ i} = R_{\mathfrak p_ i}$ which is a Noetherian local ring of dimension $2^ i$.
The ring $A$ is Noetherian.
Hence it is clear that this is the example we are looking for. Details omitted.
Post a comment
Your email address will not be published. Required fields are marked.
In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$
). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).
All contributions are licensed under the GNU Free Documentation License.
Comments (0)