17.6 Closed immersions and abelian sheaves
Recall that we think of an abelian sheaf on a topological space $X$ as a sheaf of $\underline{\mathbf{Z}}_ X$-modules. Thus we may apply any results, definitions for sheaves of modules to abelian sheaves.
Lemma 17.6.1. Let $X$ be a topological space. Let $Z \subset X$ be a closed subset. Denote $i : Z \to X$ the inclusion map. The functor
\[ i_* : \textit{Ab}(Z) \longrightarrow \textit{Ab}(X) \]
is exact, fully faithful, with essential image exactly those abelian sheaves whose support is contained in $Z$. The functor $i^{-1}$ is a left inverse to $i_*$.
Proof.
Exactness follows from the description of stalks in Sheaves, Lemma 6.32.1 and Lemma 17.3.1. The rest was shown in Sheaves, Lemma 6.32.3.
$\square$
Let $\mathcal{F}$ be an abelian sheaf on the topological space $X$. Given a closed subset $Z$, there is a canonical abelian subsheaf of $\mathcal{F}$ which consists of exactly those sections whose support is contained in $Z$. Here is the exact statement.
This seems like a good opportunity to show that the functor $i_*$ has a right adjoint on abelian sheaves.
Lemma 17.6.3. Let $i : Z \to X$ be the inclusion of a closed subset into the topological space $X$. The functor $\textit{Ab}(X) \to \textit{Ab}(Z)$, $\mathcal{F} \mapsto \mathcal{H}_ Z(\mathcal{F})$ of Remark 17.6.2 is a right adjoint to $i_* : \textit{Ab}(Z) \to \textit{Ab}(X)$. In particular $i_*$ commutes with arbitrary colimits.
Proof.
We have to show that for any abelian sheaf $\mathcal{F}$ on $X$ and any abelian sheaf $\mathcal{G}$ on $Z$ we have
\[ \mathop{\mathrm{Hom}}\nolimits _{\textit{Ab}(X)}(i_*\mathcal{G}, \mathcal{F}) = \mathop{\mathrm{Hom}}\nolimits _{\textit{Ab}(Z)}(\mathcal{G}, \mathcal{H}_ Z(\mathcal{F})) \]
This is clear because after all any section of $i_*\mathcal{G}$ has support in $Z$. Details omitted.
$\square$
Comments (0)